п»ї08. 03 Invoice discounting Trinomials x2В + bx & c

Portion 1

Element each trinomial below. You should show your function and check your answer. (1 point each)В

x2 вЂ“ 8x & 15В

(x - 3) (x -5)В

x^2 - 5x - 3x +15В

x^2 -8x + 15В

a2В вЂ“ a вЂ“ 20В

(a +4)(a-5)В

a^2 -5a +4a -20В

a2 & 12ab + 27b2В

(a +9b)(a +3b)В

a^2 + 3ab +9ab + 27b^2В

2a2 & 30a + 100В

(2a + 10)(a + 10)В

2a^2 +20a +10a + 100В

Component 2: (5 points)В

Is actually your choose be a video game show sponsor! As you know, hanging around of Mathematics Time, the contestants receive an answer and so they must develop the question that corresponds to the given response. В

Your task for this portion of the assignment should be to create two different " answersвЂќ (and the questions that accompany them) that the web host could use to get the final round of Math Time. The questions and answers you create should be unique. Check out the example and hint beneath, if necessary. В

x^2 - 95 is the item of these two binomials. В

(x & 10) (x -10)В

x^2 -10x +10x -100

My personal Solution: c = current of water b = rate of boat deb = s(t) will symbolize (distance sama dengan speed Times time) Upstream: 60 = 6(b-c) Downstream: 60 = 3(b+c)

There are now two separate equations: 60 sama dengan 6b - 6c and 60 = 3b + 3c Resolve both equations for b: b = 10 & c n = 10 - c

Now make both equations equal each other and solve pertaining to c: twelve + c = 15 - c 2c = 0 c = zero The speed with the current was 0 your Now, connect the numbers into one of either the original equations to obtain the speed from the boat in still drinking water. I chose the first equation: b sama dengan 10 + c or perhaps b sama dengan 10 + 0 b = 12

The speed with the boat in still normal water must stay a consistent 12 mph or more in order for Wayne and his little girl to make that home on time or evening meal.

My Solution: c = current of river m = level of vessel d sama dengan s(t) can represent (distance = rate X time) Upstream: 60 = 6(b-c) Downstream: 70 = 3(b+c)

There are now two separate equations: sixty = 6b - 6c and sixty = 3b + 3c Solve both equally equations for b: n = 12 + c b = 10 -- c

Now make both equations equal one another and resolve for c: 10 & c = 10 - c 2c = 0 c = 0 The velocity of the current was zero mph At this point, plug the numbers as one of both the original equations to find the velocity of the boat in continue to water. I chose the initially equation: m = twelve + c or n = twelve + zero b = 10

The speed of the vessel in nonetheless water must remain a regular 10 your or more to ensure that Wayne wonderful daughter to make it home in time or dinner.

My Solution: c = current of water b sama dengan rate of boat d = s(t) will represent (distance sama dengan speed By time) Upstream: 60 sama dengan 6(b-c) Downstream: 60 = 3(b+c)

There are now two separate equations: 60 = 6b -- 6c and 60 = 3b + 3c Resolve both equations for w: b sama dengan 10 + c m = 15 - c

Right now make both equally equations equal each other and solve intended for c: 12 + c = twelve - c 2c = 0 c = zero The speed from the current was 0 with Now, put the figures into one of either the original equations to find the speed from the boat in still drinking water. I chose the first formula: b sama dengan 10 + c or perhaps b sama dengan 10 + 0 w = 15

The speed of the boat in still drinking water must continue to be a consistent 15 mph or maybe more in order for Wayne and his girl to make that home in time or evening meal.

My Option: c sama dengan current of river b = price of boat d = s(t) will certainly represent (distance = speed X time) Upstream: sixty = 6(b-c) Downstream: sixty = 3(b+c)

There are now two separate equations: 62 = 6b - 6c and 70 = 3b + 3c Solve the two equations to get b: n = 10 + c b = 10 - c

Now generate both equations equal one another and solve for c: 10 & c sama dengan 10 - c 2c = 0 c sama dengan 0 The velocity of the current was 0 mph Right now, plug the numbers into one of both the original equations to find the velocity of the motorboat in continue to water. I selected the initial equation: m = 10 + c or n = 15 + zero b sama dengan 10

The speed of the boat in still water need to remain a consistent 10 advise or more to ensure that Wayne wonderful daughter to create it residence in time or dinner.

My Solution: c = current of river b = rate of boat g = s(t) will signify (distance = speed X time) Upstream: 60 sama dengan 6(b-c) Downstream: 60 = 3(b+c)...